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leetcode/24/11/3259.cpp
2025-09-15 21:12:04 +08:00

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#include <vector>
#include <iostream>
#include "math.h"
using namespace std;
// 3259. 能量提升
// 动态规划+贪心 递推式dp[i] += max(now[i-1], next[i-2])
long long maxEnergyBoost(vector<int> &energyDrinkA, vector<int> &energyDrinkB)
{
int n = energyDrinkA.size();
vector<vector<long long>> dp(n + 1, vector<long long>(2, 0));
dp[1][0] = energyDrinkA[0];
dp[1][1] = energyDrinkB[0];
for (int i = 2; i <= n; i++)
{
dp[i][0] = energyDrinkA[i - 1] + max(dp[i - 1][0], dp[i - 2][1]);
dp[i][1] = energyDrinkB[i - 1] + max(dp[i - 1][1], dp[i - 2][0]);
}
return max(dp[n][0], dp[n][1]);
}
long long maxEnergyBoost(int* energyDrinkA, int energyDrinkASize, int* energyDrinkB, int energyDrinkBSize) {
int n = energyDrinkASize;
long long **dp = (long long **)malloc(sizeof(long long *) * 2);
dp[0] = (long long *)malloc(sizeof(long long) * (n + 1));
dp[1] = (long long *)malloc(sizeof(long long) * (n + 1));
dp[0][0] = 0;
dp[1][0] = 0;
dp[0][1] = energyDrinkA[0];
dp[1][1] = energyDrinkB[0];
for (int i = 2; i <= n; i++)
{
dp[0][i] = energyDrinkA[i-1] + fmax(dp[0][i-1], dp[1][i-2]);
dp[1][i] = energyDrinkB[i-1] + fmax(dp[1][i-1], dp[0][i-2]);
}
return fmax(dp[0][n], dp[1][n]);
}
// 空间优化
long long maxEnergyBoost1(int* energyDrinkA, int energyDrinkASize, int* energyDrinkB, int energyDrinkBSize) {
int n = energyDrinkASize;
long long tmp[3]={energyDrinkA[0],energyDrinkB[0],energyDrinkA[0]};
for (int i = 1; i < energyDrinkASize; i++) {
tmp[0]=fmax(tmp[0]+energyDrinkA[i],tmp[1]);
tmp[1]=fmax(tmp[1]+energyDrinkB[i],tmp[2]);
tmp[2]=tmp[0];
}
return fmax(tmp[0],tmp[1]);
}